JS实现简单的图片滚动播放

发布于:2024-12-20 ⋅ 阅读:(9) ⋅ 点赞:(0)

1.效果图

请添加图片描述

2.代码实现

index.html

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <link rel="stylesheet" href="./css/index.css">
    <title>Document</title>
    <style>
        .scrollBox{
            width: 1400px;
            margin: auto;
            margin-top: 200px;
            overflow: hidden;
        }
    </style>
</head>
<body>
    <div class="scrollBox" id="scrollBox">
        <table >
            <tr>
                <td><img src="./img/01.JPG" alt="" width="350px"></td>
                <td><img src="./img/02.JPG" alt="" width="350px"></td>
                <td><img src="./img/03.JPG" alt="" width="350px"></td>
                <td><img src="./img/04.JPG" alt="" width="350px"></td>
                <td><img src="./img/01.JPG" alt="" width="350px"></td>
                <td><img src="./img/02.JPG" alt="" width="350px"></td>
                <td><img src="./img/03.JPG" alt="" width="350px"></td>
                <td><img src="./img/04.JPG" alt="" width="350px"></td>
            </tr>
        </table>
    </div>

    <script src="./js/index.js"></script>
</body>
</html>

index.js

let scrollBox = document.getElementById(`scrollBox`);//获得溢出隐藏对应的标签对象
let scrollMove = () => {//声明滚动的方法
    if (scrollBox.scrollLeft == 1400) {//判断当前是否移到了最右边
        scrollBox.scrollLeft = 0//是的话归0
    }
    scrollBox.scrollLeft+=1//不是的话继续向右移动
}
let inte = setInterval(scrollMove, 1) //设置间隔setInterval传入方法和对应毫秒数,间隔多少秒执行一次方法,并将结果付给inte
scrollBox.onmouseover = () => { //给最外面的盒子添加鼠标掠过事件
    clearInterval(inte) //鼠标掠过时,清除间隔
}
scrollBox.onmouseout = () => {//给最外面的盒子添加鼠标移出事件
    inte =setInterval(scrollMove, 1)//鼠标移出,继续执行
}


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