leetcode 61. Rotate List和86. Partition List

发布于:2025-05-28 ⋅ 阅读:(21) ⋅ 点赞:(0)

目录

61. Rotate List

 86. Partition List


61. Rotate List

代码:

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
public:
    ListNode* rotateRight(ListNode* head, int k) {
        if(head == nullptr)
            return head;
        if(k == 0)
            return head;
        ListNode* cur = head;
        int count = 0;
        while(cur){
            count++;
            cur = cur->next;
        }
        k = k%count;
        if(k == 0)
            return head;

        ListNode *pre = nullptr;
        cur = head;
        for(int i = 0;i < count -k;i++){
            pre = cur;
            cur = cur->next;
        }
        if(pre ==nullptr)
            return head;
        pre->next = nullptr;
        ListNode* newhead = cur;
        while(cur->next){
            cur = cur->next;
        }
        cur->next = head;
        return newhead;
    }
};

 86. Partition List

代码:

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
public:
    ListNode* partition(ListNode* head, int x) {
        if(head == nullptr)
            return nullptr;
        ListNode* left_dummy = new ListNode(-1,nullptr);
        ListNode* right_dummy =new ListNode(-1,nullptr);
        ListNode* leftpre = left_dummy;
        ListNode* rightpre = right_dummy;
        ListNode* cur = head;
        while(cur){
            if(cur->val < x){
                leftpre->next = cur;
                leftpre = cur;
            }else{
                rightpre->next = cur;
                rightpre = cur;
            }
            cur = cur->next;
        }
        leftpre->next = right_dummy->next;
        rightpre->next = nullptr;
        ListNode* ans = left_dummy->next;
        delete left_dummy;
        delete right_dummy;

        return ans;
    }
};

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