小游戏分享
目录
1.井字棋游戏
「3×3 棋盘上的思维博弈！与好友轮流落子，抢占先机，连成一线即可获胜。简单规则蕴含无限策略，展现你的战术智慧！」
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
char board[3][3] = {{'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'}};
int currentPlayer = 1; // 1=玩家X，2=玩家O
void printBoard() {
printf("\n");
printf(" %c | %c | %c \n", board[0][0], board[0][1], board[0][2]);
printf("---+---+---\n");
printf(" %c | %c | %c \n", board[1][0], board[1][1], board[1][2]);
printf("---+---+---\n");
printf(" %c | %c | %c \n", board[2][0], board[2][1], board[2][2]);
printf("\n");
}
bool checkWin() {
// 检查行
for (int i = 0; i < 3; i++)
if (board[i][0] == board[i][1] && board[i][1] == board[i][2])
return true;
// 检查列
for (int i = 0; i < 3; i++)
if (board[0][i] == board[1][i] && board[1][i] == board[2][i])
return true;
// 检查对角线
if (board[0][0] == board[1][1] && board[1][1] == board[2][2])
return true;
if (board[0][2] == board[1][1] && board[1][1] == board[2][0])
return true;
return false;
}
bool checkDraw() {
for (int i = 0; i < 3; i++)
for (int j = 0; j < 3; j++)
if (board[i][j] != 'X' && board[i][j] != 'O')
return false;
return true;
}
void makeMove() {
int position;
char mark = (currentPlayer == 1) ? 'X' : 'O';
printf("玩家 %d (%c) 的回合，请选择位置 (1-9): ", currentPlayer, mark);
scanf("%d", &position);
int row = (position - 1) / 3;
int col = (position - 1) % 3;
if (position >= 1 && position <= 9 && board[row][col] != 'X' && board[row][col] != 'O') {
board[row][col] = mark;
currentPlayer = (currentPlayer == 1) ? 2 : 1;
} else {
printf("无效的位置，请重试！\n");
}
}
int main() {
printf("井字棋游戏！\n");
while (1) {
printBoard();
makeMove();
if (checkWin()) {
printBoard();
printf("玩家 %d 获胜！\n", (currentPlayer == 1) ? 2 : 1);
break;
}
if (checkDraw()) {
printBoard();
printf("平局！\n");
break;
}
}
return 0;
}
2.简单计算器游戏
「数学天才的试炼场！输入数字与运算符，挑战心算极限。快速验证计算能力，在数字世界中突破自我，成为计算大师！」
#include <stdio.h>
int main() {
char operation;
double num1, num2, result;
printf("简单计算器游戏！\n");
printf("请输入操作 (+, -, *, /): ");
scanf(" %c", &operation);
printf("请输入两个数字: ");
scanf("%lf %lf", &num1, &num2);
switch (operation) {
case '+':
result = num1 + num2;
printf("%.2lf + %.2lf = %.2lf\n", num1, num2, result);
break;
case '-':
result = num1 - num2;
printf("%.2lf - %.2lf = %.2lf\n", num1, num2, result);
break;
case '*':
result = num1 * num2;
printf("%.2lf * %.2lf = %.2lf\n", num1, num2, result);
break;
case '/':
if (num2 != 0) {
result = num1 / num2;
printf("%.2lf / %.2lf = %.2lf\n", num1, num2, result);
} else {
printf("错误：除数不能为零！\n");
}
break;
default:
printf("错误：无效的操作符！\n");
}
return 0;
}
3.猜单词
「词汇探险，智破谜题！根据提示字母，逐步揭开隐藏单词的神秘面纱。考验英语词汇量，每猜对一个单词都将解锁新的挑战！」
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#include <ctype.h>
int main() {
char *words[] = {"apple", "banana", "cherry", "grape", "orange"};
int numWords = sizeof(words) / sizeof(words[0]);
char guess[50];
int attempts = 5;
int i, len, correct = 0;
char letter;
bool found;
srand(time(0));
int randomIndex = rand() % numWords;
char *word = words[randomIndex];
len = strlen(word);
char hidden[len + 1];
for (i = 0; i < len; i++) {
hidden[i] = '_';
}
hidden[len] = '\0';
printf("猜单词游戏！你有%d次机会猜出这个单词。\n", attempts);
while (attempts > 0 && strcmp(hidden, word) != 0) {
printf("当前猜测: %s\n", hidden);
printf("剩余尝试次数: %d\n", attempts);
printf("请输入一个字母: ");
scanf(" %c", &letter);
letter = tolower(letter);
found = false;
for (i = 0; i < len; i++) {
if (word[i] == letter) {
hidden[i] = letter;
found = true;
}
}
if (!found) {
attempts--;
printf("错误！这个字母不在单词中。\n");
} else {
printf("正确！这个字母在单词中。\n");
}
}
if (strcmp(hidden, word) == 0) {
printf("恭喜你，猜对了！单词是: %s\n", word);
} else {
printf("游戏结束！正确的单词是: %s\n", word);
}
return 0;
}4.石头剪刀布游戏
「指尖对决，策略至上！石头、布、剪刀，三选一的永恒谜题。击败 AI 对手，成为不败王者，体验经典游戏的全新魅力！」
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main() {
int player, computer;
srand(time(0));
computer = rand() % 3 + 1; // 1=石头，2=布，3=剪刀
printf("石头剪刀布游戏！\n");
printf("请选择: 1=石头, 2=布, 3=剪刀: ");
scanf("%d", &player);
printf("你选择了: ");
switch (player) {
case 1: printf("石头\n"); break;
case 2: printf("布\n"); break;
case 3: printf("剪刀\n"); break;
default: printf("无效选择\n"); return 1;
}
printf("电脑选择了: ");
switch (computer) {
case 1: printf("石头\n"); break;
case 2: printf("布\n"); break;
case 3: printf("剪刀\n"); break;
}
// 判断胜负
if (player == computer)
printf("平局！\n");
else if ((player == 1 && computer == 3) ||
(player == 2 && computer == 1) ||
(player == 3 && computer == 2))
printf("你赢了！\n");
else
printf("你输了！\n");
return 0;
}5.猜数字游戏
「数字迷踪，智胜挑战！我已锁定 1-100 之间的神秘数字，每轮猜测都将获得精准提示。用最少的尝试揭开谜底，展现你的逻辑推理天赋！」
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main() {
int number, guess, attempts = 0;
srand(time(0));
number = rand() % 100 + 1; // 生成1-100之间的随机数
printf("猜数字游戏！我已经想好了一个1到100之间的数字，你可以开始猜了...\n");
do {
printf("请输入你的猜测: ");
scanf("%d", &guess);
attempts++;
if (guess > number)
printf("猜的数字太大了！再试一次。\n");
else if (guess < number)
printf("猜的数字太小了！再试一次。\n");
else
printf("恭喜你，猜对了！你用了%d次尝试。\n", attempts);
} while (guess != number);
return 0;
}