C语言--实现会动的爱心

发布于:2023-10-25 ⋅ 阅读:(145) ⋅ 点赞:(0)

爱心代码

C语言学习了那么是否想换个花样来学习

运行环境

devc++
话不多说上代码

代码实现

#include <stdio.h>
#include <math.h>
#include <windows.h>
#include <tchar.h>

float f(float x, float y, float z) {
float a = x * x + 9.0f / 4.0f * y * y + z * z - 1;
return a * a * a - x * x * z * z * z - 9.0f / 80.0f * y * y * z * z * z;
}

float h(float x, float z) {
  for (float y = 1.0f; y >= 0.0f; y -= 0.001f)
if (f(x, y, z) <= 0.0f)
return y;
return 0.0f;
}

int main() {
HANDLE o = GetStdHandle(STD_OUTPUT_HANDLE);
_TCHAR buffer[25][80] = { _T(' ') };
_TCHAR ramp[] = _T(".:-=+*#%@");

for (float t = 0.0f;; t += 0.1f) {
    int sy = 0;
    float s = sinf(t);
    float a = s * s * s * s * 0.2f;
    for (float z = 1.3f; z > -1.2f; z -= 0.1f) {
    _TCHAR* p = &buffer[sy++][0];
    float tz = z * (1.2f - a);
    for (float x = -1.5f; x < 1.5f; x += 0.05f) {
    float tx = x * (1.2f + a);
    float v = f(tx, 0.0f, tz);
    if (v <= 0.0f) {
    float y0 = h(tx, tz);
    float ny = 0.01f;
    float nx = h(tx + ny, tz) - y0;
    float nz = h(tx, tz + ny) - y0;
    float nd = 1.0f / sqrtf(nx * nx + ny * ny + nz * nz);
    float d = (nx + ny - nz) * nd * 0.5f + 0.5f;
    *p++ = ramp[(int)(d * 5.0f)];
}
else
    *p++ = ' ';
}
}

    for (sy = 0; sy < 25; sy++) {
    COORD coord = { 0, sy };
    SetConsoleCursorPosition(o, coord);
    WriteConsole(o, buffer[sy], 79, NULL, 0);
}
Sleep(33);
}
}

运行结果

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在这里插入图片描述

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