MYSQL直接在SQL提取json字符串中的内容-----将13位时间戳转换成标准的日期格式【记录SQL常用函数】

发布于:2025-02-15 ⋅ 阅读:(18) ⋅ 点赞:(0)


1.如果表中某个字段中存的是JOSN,那么mysql可以使用JSON_EXTRACT函数来进行字符串的解析。

字段内容如下所示:
[{
    "tax": {
        "taxName": "Tax1",
        "taxAmount": {
            "amount": 0,
            "currency": "USD"
        }
    },
    "chargeName": "ItemPrice",
    "chargeType": "PRODUCT",
    "chargeAmount": {
        "amount": 499.99,
        "currency": "USD"
    }
}]

SELECT JSON_EXTRACT(charges, '$[0].tax.taxAmount.amount')  AS tax_amount,
       JSON_EXTRACT(charges, '$[0].chargeAmount.amount')   AS charge_amount,
       JSON_EXTRACT(charges, '$[0].chargeAmount.currency') AS currency
FROM your_table
WHERE line_id = xxx;
SELECT
    JSON_EXTRACT(charges, '$[0].tax.taxAmount.amount') AS tax_amount,
    JSON_EXTRACT(charges, '$[0].chargeAmount.amount') AS charge_amount,
    JSON_EXTRACT(charges, '$[0].chargeAmount.currency') AS currency
FROM
    your_table WHERE line_id=xxx;

查询结果 如下

2.将13位时间戳转换成标准的日期格式

例如数据库中某些时间字段记录的是 1688041306058 这样的时间戳

mysql可以使用 FROM_UNIXTIME() 来对时间戳进行转换

SELECT FROM_UNIXTIME(your_timestamp_column / 1000) AS standard_time FROM your_table;

SELECT DATE_FORMAT(FROM_UNIXTIME(your_timestamp_column / 1000), '%Y-%m-%d %H:%i:%s') AS formatted_time FROM your_table;

SELECT FROM_UNIXTIME(1688041306058 / 1000) ;

SELECT DATE_FORMAT(FROM_UNIXTIME(1688041306058 / 1000), '%Y-%m-%d %H:%i:%s');